Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 590: 10

Answer

$x =\dfrac{\log{2}}{\log{6}} - 3 \\x \approx -2.6131$

Work Step by Step

Take the common logarithm of both sides to have: $\log{(6^{x+3})}=\log{2}$ Apply the power property of logarithms to have: $(x+3)(\log{6}) = \log{2}$ Divide $\log{6}$ to both sides to have: $\\x+3 = \dfrac{\log{2}}{\log{6}}$ Subtract $3$ to both sides to have: $\\x =\dfrac{\log{2}}{\log{6}} - 3 \\x \approx -2.6131$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.