Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 590: 24

Answer

$x =\dfrac{\frac{\log{12}}{\log{5}}+6}{2} \approx 3.7720$

Work Step by Step

Take the common logarithm of both sides to have: $\log{(5^{2x-6})}=\log{12}$ Apply the power rule to have: $(2x-6)\log{5}=\log{12}$ Divide $\log{5}$ to both sides to have: $2x-6=\dfrac{\log{12}}{\log{5}} \\2x=\dfrac{\log{12}}{\log{5}}+6 \\x =\dfrac{\frac{\log{12}}{\log{5}}+6}{2} \approx 3.7720$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.