Answer
$x = \dfrac{\log{6}}{\log{3}} \approx 1.6309$
Work Step by Step
Take the common logarithm of both sides to have:
$\log{3^x}=\log{6}$
Apply the power property of logarithms to have:
$x(\log{3}) = \log{6}$
Divide $\log{3}$ to both sides to have:
$\\x = \dfrac{\log{6}}{\log{3}}
\\x \approx 1.6309$
