Answer
$d=\sqrt {65}$
Work Step by Step
$a^2=16$
$\sqrt {a^2} = \sqrt {16}$
$a = 4$
$b^2=65$
$\sqrt {b^2} = \sqrt {65}$
$b = \sqrt {65}$
$\sqrt {65} > 4$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 64g
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