Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 32

See graph

$$3x^2+12y^2=48$$ $$\frac{x^2}{16}+\frac{y^2}{4}=1$$ This is an ellipse. The center is (0,0). The vertices are 4 units away from the center in the x-direction: (4,0) and (-4,0). The covertices are 2 unit away from the center in the y-direction: (0,2) and (0,-2). Plot these points and connect with a smooth ellipse.