Answer
See graph
Work Step by Step
$$16y^2-x^2=16$$
$$y^2-\frac{x^2}{16}=1$$
The center of the hyperbola is (0,0). The four corners of the box are (4,1), (-4,1), (4,-1) and (-4,-1). Draw a dotted box through these points. Then draw two dotted lines through the corners. The vertices of the hyperbola are (0,1) and (0,-1), so plot those points and draw a smooth curve nearing the two asymptotes without touching them.
