Answer
See graph
Work Step by Step
$$25(x+3)^2+4(y-3)^2=100$$
$$\frac{(x+3)^2}{4}+\frac{(y-3)^2}{25}=1$$
This is an ellipse. The center is (-3,3). The vertices are 5 units away from the center in the y-direction: (-3,8) and (-3,-2). The covertices are 2 unit away from the center in the x-direction: (-1,3) and (-5,3). Plot these points and connect with a smooth ellipse.
