Answer
See graph
Work Step by Step
$$x=y^2+4y-1$$
$$x+1=y^2+4y$$
Complete the square.
$$x+1+4=y^2+4y+4$$
$$x+5=(y+2)^2$$
$$x=(y+2)^2-5$$
This is a parabola with vertex (5,-2).
Substitute -4 for x.
$$-4=(y+2)^2-5$$
$$1=(y+2)^2$$
$$1=y+2$$
$$y=-1$$
$$-1=y+2$$
$$y=-3$$
$$(-4,-1)$$
$$(-4,-3)$$
Plot these points and connect with a smooth curve.
