Answer
$d=\sqrt {39}$
Work Step by Step
$a^2=39$
$\sqrt {a^2} = \sqrt {39}$
$a = \sqrt {39}$
$b^2=25$
$\sqrt {b^2} = \sqrt {25}$
$b = 5$
$\sqrt {39} >5$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 64d
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