Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Exercise Set - Page 618: 64e

Answer

$d=9$

Work Step by Step

$a^2=17$ $\sqrt {a^2} = \sqrt {17}$ $a = \sqrt {17}$ $b^2=81$ $\sqrt {b^2} = \sqrt {81}$ $b = 9$ $\sqrt {17} < 9 $
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