Answer
$y-5=\dfrac{1}{2}(x-2)$
Work Step by Step
Using the properties of equality, the given linear equation, $
x-2y=3
$ is equivalent to
\begin{array}{l}
-2y=-x+3
\\\\
y=\dfrac{-1}{-2}x+\dfrac{3}{-2}
\\\\
y=\dfrac{1}{2}x-\dfrac{3}{2}
.\end{array}
Using $y=mx+b$ or the Slope-Intercept form where $m$ is the slope, then the slope of the given line is $
\dfrac{1}{2}
$. Since parallel lines have the same slope, then the needed linear equation has the same slope and it passes through the given point $(
2,5
)$. Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the needed line is
\begin{array}{l}
y-5=\dfrac{1}{2}(x-2)
.\end{array}
