Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 14

$\text{slope: } \dfrac{4}{5} ,\\\text{a point on the line: } (0,0)$

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the given equation, $ y=\dfrac{4}{5}x $, has the following characteristics: \begin{array}{l} \text{slope: } \dfrac{4}{5} ,\\\text{a point on the line: } (0,0) .\end{array}