Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 46

$y=\dfrac{1}{4}x+3$

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the line with the given slope equal to $ \dfrac{1}{4} $ and with the given point $\left( 0,3 \right)$ is \begin{array}{l} y-3=\dfrac{1}{4}(x-0) \\\\ y-3=\dfrac{1}{4}x \\\\ y=\dfrac{1}{4}x+3 .\end{array}