Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 43

$y=-0.6x-5.8$

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the line with the given slope equal to $ -0.6 $ and with the given point $\left( -3,-4 \right)$ is \begin{array}{l} y-(-4)=-0.6(x-(-3)) \\\\ y+4=-0.6(x+3) \\\\ y+4=-0.6x-1.8 \\\\ y=-0.6x-1.8-4 \\\\ y=-0.6x-5.8 .\end{array}