Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 44

$y=2.3x-14.2$

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the line with the given slope equal to $ 2.3 $ and with the given point $\left( 4,-5 \right)$ is \begin{array}{l} y-(-5)=2.3(x-4) \\\\ y+5=2.3x-9.2 \\\\ y=2.3x-9.2-5 \\\\ y=2.3x-14.2 .\end{array}