Chapter 3 - Introduction to Graphing - 3.7 Point-Slope Form and Equations of Lines - 3.7 Exercise Set - Page 218: 40

$y=-4x+1$

Using $y-y_1=m(x-x_1)$ or the Point-Slope form where $m$ is the slope and $(x_1,y_1)$ is a point on the line, then the equation of the line with the given slope equal to $ -4 $ and with the given point $\left( -1,5 \right)$ is \begin{array}{l} y-5=-4(x-(-1)) \\\\ y-5=-4(x+1) \\\\ y-5=-4x-4 \\\\ y=-4x-4+5 \\\\ y=-4x+1 .\end{array}