Answer
Refer to the graph below.
Work Step by Step
RECALL:
The point-slope form of a line's equation is given by $y-y_1=m(x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point on the line.
Thus, the given equation $y-2=3(x-5)$ has:
$m=3$
$(5, 2)$ is a point on the line.
To graph this equation, perform the following steps:
(1) Plot the point $(5, 2)$.
(2) Use the slope to plot another point on the line. From $(5, 2)$ move 3 units up (the rise) and 1 unit to the right (the run) to reach $(6, 5)$. Plot $(6, 5)$.
(3) Connect the two points using a line.
