Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 37

$x\approx15.849$

In exponential form, the given logarithmic equation, $ \log x =1.2 ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{10} x =1.2 \\\\ x=10^{1.2} .\end{array} Hence, the value of the variable that satisfies the given equation is \begin{array}{l}\require{cancel} x\approx15.849 .\end{array}