Answer
$x\approx2.996$
Work Step by Step
Taking the natural logarithm of both sides and using the properties of logarithms, the value of the variable that satisfies the given equation, $
e^t=20
,$ is
\begin{array}{l}\require{cancel}
\ln e^t=\ln20
\\\\
t\ln e=\ln20
\\\\
t(1)=\ln20
\\\\
t=\ln20
\\\\
x\approx2.996
.\end{array}