Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 825: 10

$x=2$

Using exponents, the given equation, $ 2^{3x}=64 ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{3x}=2^6 .\end{array} Since the bases are the same, the exponents can be equated. Hence, \begin{array}{l}\require{cancel} 3x=6 \\\\ x=\dfrac{6}{3} \\\\ x=2 .\end{array}