Answer
$m=-\dfrac{7}{10}$
Work Step by Step
With the given points, $(8,3)$ and $(-2,10)$, let
\begin{align*}
y_1=
3
,\\y_2=
10
,\\x_1=
8
,\text{ and }\\ x_2=
-2
.\end{align*}
Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line passing through the given points is
\begin{align*}
m&=\dfrac{3-10}{8-(-2)}
\\\\&=
\dfrac{3-10}{8+2}
\\\\&=
\dfrac{-7}{10}
\\\\&=
-\dfrac{7}{10}
.\end{align*}
Hence, the slope, $m,$ of the line containing $(8,3)$ and $(-2,10)$ is $m=-\dfrac{7}{10}$.
