Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-11 - Cumulative Review - Page 776: 2

Answer

$14x^2y-10xy-9xy^2$

Work Step by Step

By removing first the grouping symbols, the given expression, $ (5x^2y-8xy-6xy^2)-(2xy-9x^2y+3xy^2) ,$ is equivalent to \begin{align*} & (5x^2y-8xy-6xy^2)-2xy+9x^2y-3xy^2 &(\text{alter the signs}) \\& 5x^2y-8xy-6xy^2-2xy+9x^2y-3xy^2 .\end{align*} By combining the like terms next, the expression above is equivalent to \begin{align*} & (5x^2y+9x^2y)+(-8xy-2xy)+(-6xy^2-3xy^2) \\&= 14x^2y-10xy-9xy^2 .\end{align*} Hence, the expression $(5x^2y-8xy-6xy^2)-(2xy-9x^2y+3xy^2)$ simplifies to $14x^2y-10xy-9xy^2$.
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