Answer
$\dfrac{n^{3}}{8}$
Work Step by Step
Using the laws of exponents, the given expression, $
(2n^{-1})^{-3}
,$ simplifies to
\begin{array}{l}\require{cancel}
2^{-3}n^{-1(-3)}
\\\\=
2^{-3}n^{3}
\\\\=
\dfrac{n^{3}}{2^3}
\\\\=
\dfrac{n^{3}}{8}
.\end{array}
