Answer
$7a^3b^4$
Work Step by Step
We use the rules of exponents to obtain:
$\frac{-56a^5b^7}{-8a^2b^3}=\frac{-56}{-8}\times\frac{a^5}{a^2}\times\frac{b^7}{b^3}=7\times a^{5-2}\times b^{7-3}=7a^3b^4$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set - Page 231: 42
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