Answer
$\dfrac{4}{n}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{48n^{-2}}{12n^{-1}}
,$ simplifies to
\begin{array}{l}\require{cancel}
(48\div12)n^{-2-(-1)}
\\\\=
4n^{-2+1}
\\\\=
4n^{-1}
\\\\=
\dfrac{4}{n^1}
\\\\=
\dfrac{4}{n}
.\end{array}
