Answer
$x^3-3x^2+8x-12$
Work Step by Step
RECALL:
The distributive property states that for any real numbers a, b, and c:
$a(b+c) = ab+ac
\\a(b-c) = ab - ac$
Use the distributive property (which is shown above) to obtain:
$=x(x^2-x+6)-2(x^2-x+6)
\\=x(x^2)+x(-x) +x(6)-2(x^2) -2(-x) -2(6)
\\=x^3-x^2+6x-2x^2+2x-12$
Combine like terms to obtain:
$=x^3 + (-x^2-2x^2)+(6x+2x)-12
\\=x^3+(-3x^2)+8x-12
\\=x^3-3x^2+8x-12$
