Answer
$\dfrac{x^{2}}{y}$
Work Step by Step
Using the laws of exponents, the given expression, $
(x^{-2}y)^{-1}
,$ simplifies to
\begin{array}{l}\require{cancel}
x^{-2(-1)}y^{1(-1)}
\\\\=
x^{2}y^{-1}
\\\\=
\dfrac{x^{2}}{y^1}
\\\\=
\dfrac{x^{2}}{y}
.\end{array}
