Answer
$-3x^2y-9x^4$
Work Step by Step
We use the rules of exponents to obtain:
$\frac{-18x^4y^3-54x^6y^2}{6x^2y^2}= \frac{-18x^4y^3}{6x^2y^2}-\frac{54x^6y^2}{6x^2y^2}=-3x^2y-9x^4$
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