Answer
4/7
Work Step by Step
Recall, when a number is raised to the second power, the square root cancels out the exponent, and when a number is raised to the third power, the cube root cancels out the exponent. Thus, we obtain:
$ \sqrt[3] {64}/\sqrt{49} = \sqrt[3] {4^{3}}/ \sqrt{7^{2}}=4/7$
