Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 58

Answer

$18x^{\frac{13}{20}}$

Work Step by Step

Recall the following rule: $a^{n}\cdot a^{m}=a^{n+m}$. Therefore, we obtain: $(3x^{\frac{2}{5}})(6x^{\frac{1}{4}})$ $=(3\times6)(x^{\frac{2}{5}+\frac{1}{4}})$ $=(18)(x^{\frac{2(4)+5(1)}{20}})$ $=18x^{\frac{13}{20}}$
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