Answer
$56n^{\frac{1}{2}}$
Work Step by Step
Recall the following rule: $a^{n}\cdot a^{m}=a^{n+m}$. Therefore, we obtain:
$(7n^{-\frac{1}{3}})(8n^{\frac{5}{6}})$
$=(7\times8)(n^{-\frac{1}{3}+\frac{5}{6}})$
$=(56)(n^{\frac{-2+5}{6}})$
$=56n^{\frac{3}{6}}$
$=56n^{\frac{1}{2}}$
