Answer
3
Work Step by Step
We will use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ in the simplification of the expression:
$\frac{27n^{-\frac{1}{3}}}{9n^{-\frac{1}{3}}}$
$=\frac{27}{9}\times\frac{n^{-\frac{1}{3}}}{n^{-\frac{1}{3}}}$
$=3\times n^{-\frac{1}{3}+(\frac{1}{3})}$
$=3\times n^{\frac{-1+1}{3}}$
$=3\times n^{\frac{0}{3}}$
$=3\times n^{0}$
$=3\times 1$
$=3$
