Answer
$a^{\frac{1}{12}}$
Work Step by Step
Recall the following rule: $a^{n}+a^{m}=a^{n+m}$
Thus, we obtain:
$a^{\frac{1}{3}}\times a^{-\frac{1}{4}}$
=$a^{\frac{1}{3}-\frac{1}{4}}$
=$a^{\frac{1(4)-1(3)}{12}}$
=$a^{\frac{4-3}{12}}$
=$a^{\frac{1}{12}}$
