Answer
$2x^{\frac{-1}{6}}$
Work Step by Step
We will use the rule $a^{n}a^{m}=a^{n+m}$ in the solution. Therefore,
$(2x^{\frac{1}{3}})(x^{-\frac{1}{2}})$
$=(2\times1)(x^{\frac{1}{3}-\frac{1}{2}})$
$=(2)(x^{\frac{2-3}{6}})$
$=2x^{\frac{-1}{6}}$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 63
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