Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 2 - Matrices and Systems of Linear Equations - 2.2 Matrix Algebra - Problems - Page 135: 13

Answer

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Work Step by Step

$A^2=A.A=\begin{bmatrix} 2 & -5\\ 6 & -6 \end{bmatrix}.\begin{bmatrix} 2 & -5\\ 6 & -6 \end{bmatrix}=\begin{bmatrix} -26 & 20\\ -24 & 6 \end{bmatrix}$ $4A=4\begin{bmatrix} 2 & -5\\ 6 & -6 \end{bmatrix}=\begin{bmatrix} 8 & -20\\ 24 & -24 \end{bmatrix}$ Hence $A^2+4A+18I_2=\begin{bmatrix} -26 & 20\\ -24 & 6 \end{bmatrix}+\begin{bmatrix} 8 & -20\\ 24 & -24 \end{bmatrix}+\begin{bmatrix} 18 & 0\\ 0 &18 \end{bmatrix}=\begin{bmatrix} 0 & 0\\ 0&0 \end{bmatrix}$
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