Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 4 - Writing Linear Functions - 4.2 - Writing Equations in Point-Slope Form - Exercises - Page 185: 28

Answer

The data in the table can be modeled by a linear equation. The linear equation is $y=-3x+7$.

Work Step by Step

The rate of change for consecutive data pairs in the table. $\Rightarrow \frac{10-16}{-1-(-3)}=\frac{-6}{-1+3}=-\frac{6}{2}=-3$ $\Rightarrow \frac{4-10}{1-(-1)}=\frac{-6}{1+1}=-\frac{6}{2}=-3$ $\Rightarrow \frac{-2-4}{3-1}=-\frac{6}{2}=-3$ $\Rightarrow \frac{-8-(-2)}{5-3}=\frac{-8+2}{2}=-\frac{6}{2}=-3$ Because the rate of change is constant, the data in the table can be modeled by a linear equation. Slope is $m=-3$ Use the point $(x_1,y_1)=(1,4)$ The point-slope form is $\Rightarrow y-y_1=m(x-x_1)$ Substitute $-3$ for $m,1$ for $x_1$ and $4$ for $y_1$. $\Rightarrow y-4=-3(x-1)$ Use distributive property. $\Rightarrow y-4=-3x+3$ Add $4$ to each side. $\Rightarrow y=-3x+7$
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