Answer
Slope $m=-2$
Point= $(-5,5)$
Work Step by Step
Equation of line in slope-intercept form is
$y-y_{1}=m(x-x_{1})$
Comparing the given equation $y-5=-2(x+5)$ with the slope-intercept form, we get
$y_{1}=5$, $m=-2$ and $x_{1}=-5$
So, one point on the line is $(-5,5)$