Answer
$y=-\frac{3}{5}x+16$
Work Step by Step
Let $(x_{1},y_{1})=(-5,19)$ and $(x_{2},y_{2})=(5,13)$
The slope of the line is
$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{13-19}{5-(-5)}=\frac{-6}{10}=-\frac{3}{5}$
We can write the equation of a line using the value of slope $m=-\frac{3}{5}$ and the point $(-5,19)$.
$y-y_{1}=m(x-x_{1})$
$\implies y-19=-\frac{3}{5}(x-(-5))$
$\implies y-19=-\frac{3}{5}(x+5)$
$\implies y=-\frac{3}{5}x-3+19$
$\implies y=-\frac{3}{5}x+16$
