Answer
$\lt \dfrac{9}{5},\dfrac{12}{5} \gt$
Work Step by Step
We are given that $||\overrightarrow{v}|| = 3$.
So, $ \cos \theta =\dfrac{3}{5}; \sin \theta =\dfrac{4}{5}$
We know that $v=||v|| \lt \cos \theta , \sin \theta \gt $
Thus, $v=3 \lt \dfrac{3}{5},\dfrac{4}{5} \gt \\= \lt (3) (\dfrac{3}{5}),(3) (\dfrac{4}{5} ) \gt \\= \lt \dfrac{9}{5},\dfrac{12}{5} \gt$
