Answer
<1, 0>
Work Step by Step
$\overrightarrow{v} = <3, 0>$
To find the unit vector, we must first find the magnitude:
$\sqrt {((3)^{2} + (0)^{2}}$ = 3
We can then write the unit vector:
$\widehat{v} = $ = <1, 0>
To verify that it is a unit vector, we find the magnitude:
$\sqrt {((1)^{2} + (0)^{2}}$ = 1
Since the magnitude equals 1, it is a unit vector.
