Answer
$ \lt 3, 0 \gt$
Work Step by Step
We are given that $||\overrightarrow{v}|| = 3$ and that:
$ \theta =0^{\circ}$
We know that $v=||v|| \lt \cos \theta , \sin \theta \gt $
Thus, $v=3 \lt 1,0 \gt = \lt 3, 0 \gt$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 586: 65
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