Answer
$\lt 0, 4 \sqrt 3 \gt$
Work Step by Step
We are given that $||\overrightarrow{v}|| = 4 \sqrt 3$ and that:
$ \theta = 90^{\circ}$
We know that $v=||v|| \lt \cos \theta , \sin \theta \gt $
Thus, $v=4 \sqrt 3 \lt \cos 90^{\circ} , \sin 90^{\circ} \gt =4 \sqrt 3 \lt 0, 1 \gt = \lt 0, 4 \sqrt 3 \gt$
