Answer
<0, -1>
Work Step by Step
$\overrightarrow{v} = <0, -2>$
To find the unit vector, we must first find the magnitude:
$\sqrt {((0)^{2} + (-2)^{2}}$ = 2
We can then write the unit vector:
$\widehat{v} = $ = <0, -1>
To verify that it is a unit vector, we find the magnitude:
$\sqrt {((0)^{2} + (-1)^{2}}$ = 1
Since the magnitude equals 1, it is a unit vector.
