Answer
$10^{5.1}$ times
Work Step by Step
We are given the model: $[pH]_{\ juice} =2.9$ and $[pH]_{\ water} =8.0$
$[p H]=-\log [H^{+}]$
Or, $[H^{+}]= 10^{-[p H]}$
Now, $\dfrac{[H^{+}]_{\ juice}}{[H^{+}]_{\ water}} =\dfrac{10^{-2.9}}{10^{-8}}$
or, $=10^{-2.9 -(-8) }$
or, $=10^{5.1}$ times