Answer
$4.64$
Work Step by Step
We are given the model: $pH =- \log H^{+}$
Plug in the data:
Therefore, $pH =- \log 2.3 \times 10^{-5}$
Or, $pH =- \log 2.3 \times 10^{-5} \approx 4.64$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 51
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