Answer
$-220$ decibels
Work Step by Step
We have $\beta=10 \log (II_0)$
Therefore, $\beta=10 \log (10^{-10} \times 10^{-12})= 10 \log 10^{-22}$
Or, $\beta = 10 (-22) \log 10 =-220$
Therefore, the sound level is $\beta = -220$ decibels
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