Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 48c

$-160$ decibels

We have $\beta=10 \log (II_0)$ Plug in the data: Therefore, $\beta=10 \log (10^{-12} \times 10^{-4})= 10 \log 10^{-16}$ Or, $\beta = 10 (-16) \log 10 =10 \times (-16) \times (1)=-160$ Therefore, the sound level is $\beta = -160$ decibels