Answer
$1.58 \times 10^{-6}$
Work Step by Step
We are given the model: $pH =- \log [H^{+}]$
Therefore, $5.8=- \log [H^{+}]$
Or, $-5.8= \log [H^{+}]$
or, $10^{-5.8}=[H^{+}]$
Therefore, $[H^{+}]=1.58 \times 10^{-6}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 53
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