Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 48b

$ -100$ decibels

We have $\beta=10 \log (II_0)$ Plug in the data: Therefore, $\beta=10 \log (10^{-12} \times 10^{2})= 10 \log 10^{-10}$ Or, $\beta = 10 (-10) \log 10 =10 \times (-10) \times (1)=-100$ Therefore, the sound level is $\beta = -100$ decibels