Answer
$\beta=90~decibels$
Work Step by Step
$\beta=10\log(\frac{I}{I_0})$
$\beta=10\log(\frac{10^{-3}}{10^{-12}})=10\log(10^{-3-(-12)})=10\log(10^9)=10(9)=90$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 47d
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